# Problem What is the binary equivalent of `0xBEAD`? # Process $\textrm{B}_{16}=1011_2$ $\textrm{E}_{16}=1110_2$ $\textrm{A}_{16}=1010_2$ $\textrm{D}_{16}=1101_2$ $\begin{split} \textrm{BEAD}_{16}&=\overbracket{1011_2}^{\textrm{B}_{16}}\overbracket{1110_2}^{\textrm{E}_{16}}\overbracket{1010_2}^{\textrm{A}_{16}}\overbracket{1101_2}^{\textrm{D}_{16}}\\ &=\boxed{1011111010101101_2} \end{split}$ # Answer ``` 0b1011111010101101 ```